Mathematics · 2022
JEE Main · 26 June 2022, Shift 2 · Q8
If ∫ 1/x √((1-x)/(1+x)) d x=g(x)+c, g(1)=0, then g(1/2) is equal to:
If $\displaystyle \int \frac{1}{x} \sqrt{\frac{1-x}{1+x}} d x=g(x)+c, g(1)=0$, then $\displaystyle g\left(\frac{1}{2}\right)$ is equal to :
Official answer
(1)
$\displaystyle \log _e\left(\frac{\sqrt{3}-1}{\sqrt{3}+1}\right)+\frac{\pi}{3}$
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JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.