Mathematics · 2021
JEE Main · 31 August 2021, Shift 2 · Q70
If (d y)/(d x)=(2^x y+2^y · 2^x)/(2^x+2^x+y log_e 2), y(0)=0, then for y=1, the value of x lies in the interval:
If $\displaystyle \frac{\mathrm{d} y}{\mathrm{~d} x}=\frac{2^x y+2^y \cdot 2^x}{2^x+2^{x+y} \log _{\mathrm{e}} 2}, y(0)=0$, then for $\displaystyle y=1$, the value of $\displaystyle x$ lies in the interval :
Official answer
(3)
$\displaystyle (1,2)$
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.