Mathematics · 2022
JEE Main · 24 June 2022, Shift 1 · Q14
If x=x(y) is the solution of the differential equation y (d x)/(d y)=2 x+y^3(y+1) e^y, x(1)=0; then x( e ) is equal to:
If $\displaystyle x=x(y)$ is the solution of the differential equation $\displaystyle y \frac{\mathrm{~d} x}{\mathrm{~d} y}=2 x+y^3(y+1) \mathrm{e}^y, x(1)=0$; then $\displaystyle x(\mathrm{e})$ is equal to :
Official answer
(1)
$\displaystyle \mathrm{e}^3\left(\mathrm{e}^{\mathrm{e}}-1\right)$
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JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.