Mathematics · 2019
JEE Main · 8 April 2019, Shift 1 · Q82
If the tangents on the ellipse 4 x^2+y^2=8 at the points (1,2) and (a, b) are perpendicular to each other, then a^2 is equal to:
If the tangents on the ellipse $\displaystyle 4 x^2+y^2=8$ at the points $\displaystyle (1,2)$ and (a, b) are perpendicular to each other, then $\displaystyle \mathrm{a}^2$ is equal to :
Official answer
(1)
$\displaystyle \frac{2}{17}$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.