Mathematics · 2019
JEE Main · 9 April 2019, Shift 2 · Q82
If the tangent to the parabola y^2=x at a point (α, β),(β>0) is also a tangent to the ellipse, x^2+2 y^2=1, then α is equal to:
If the tangent to the parabola $\displaystyle y^2=x$ at a point $\displaystyle (\alpha, \beta),(\beta>0)$ is also a tangent to the ellipse, $\displaystyle x^2+2 y^2=1$, then $\displaystyle \alpha$ is equal to:
Official answer
(1)
$\displaystyle \sqrt{2}+1$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.