Mathematics · 2025
JEE Main · 4 April 2025, Shift 2 · Q5
If the sum of the first 20 terms of the series (4 · 1)/(4+3 · 1^2+1^4)+(4 · 2)/(4+3 · 2^2+2^4)+(4 · 3)/(4+3 · 3^2+3^4)+(4 · 4)/(4+3 · 4^2+4^4)+…. is…
If the sum of the first $\displaystyle 20$ terms of the series $\displaystyle \frac{4 \cdot 1}{4+3 \cdot 1^2+1^4}+\frac{4 \cdot 2}{4+3 \cdot 2^2+2^4}+\frac{4 \cdot 3}{4+3 \cdot 3^2+3^4}+\frac{4 \cdot 4}{4+3 \cdot 4^2+4^4}+\ldots$. is $\displaystyle \frac{\mathrm{m}}{\mathrm{n}}$, where m and n are coprime, then $\displaystyle \mathrm{m}+\mathrm{n}$ is equal to :
Official answer
From NTA’s final answer key for this paper.
(2)
$\displaystyle 421$
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JEE Main 2025 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.