Mathematics · 2025
JEE Main · 7 April 2025, Shift 1 · Q6
Let x_1, x_2, x_3, x_4 be in a geometric progression. If 2, 7, 9, 5 are subtracted respectively from x_1, x_2, x_3, x_4, then the resulting numbers…
Let $\displaystyle x_1, x_2, x_3, x_4$ be in a geometric progression. If $\displaystyle 2$, $\displaystyle 7$, $\displaystyle 9$, $\displaystyle 5$ are subtracted respectively from $\displaystyle x_1, x_2, x_3, x_4$, then the resulting numbers are in an arithmetic progression. Then the value of $\displaystyle \frac{1}{24}\left(x_1 x_2 x_3 x_4\right)$ is:
Official answer
From NTA’s final answer key for this paper.
(1)
$\displaystyle 216$
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JEE Main 2025 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.