Consider two sets A and B, each containing three numbers in A.P. Let the sum and the product of the elements of A be 36 and p respectively and the…

Consider two sets A and B, each containing three numbers in A.P. Let the sum and the product of the elements of A be $\displaystyle 36$ and p respectively and the sum and the product of the elements of B be $\displaystyle 36$ and q respectively. Let d and D be the common differences of AP's in A and B respectively such that $\displaystyle \mathrm{D}=\mathrm{d}+3, \mathrm{~d}>0$. If $\displaystyle \frac{\mathrm{p}+\mathrm{q}}{\mathrm{p}-\mathrm{q}}=\frac{19}{5}$, then $\displaystyle \mathrm{p}-\mathrm{q}$ is equal to