If the shortest distance between the lines (x-λ)/2=(y-4)/3=(z-3)/4 and (x-2)/4=(y-4)/6=(z-7)/8 is 13/(√ 29), then a value of λ is:

If the shortest distance between the lines $\displaystyle \frac{x-\lambda}{2}=\frac{y-4}{3}=\frac{z-3}{4}$ and $\displaystyle \frac{x-2}{4}=\frac{y-4}{6}=\frac{z-7}{8}$ is $\displaystyle \frac{13}{\sqrt{29}}$, then a value of $\displaystyle \lambda$ is :