If the shortest distance between the lines (x-λ)/-2=(y-2)/1=(z-1)/1 and (x-√ 3)/1=(y-1)/-2=(z-2)/1 is 1, then the sum of all possible values of λ is:

If the shortest distance between the lines $\displaystyle \frac{x-\lambda}{-2}=\frac{y-2}{1}=\frac{z-1}{1}$ and $\displaystyle \frac{x-\sqrt{3}}{1}=\frac{y-1}{-2}=\frac{z-2}{1}$ is $\displaystyle 1$ , then the sum of all possible values of $\displaystyle \lambda$ is :