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Mathematics · 2024

JEE Main · 1 February 2024, Shift 2 · Q15

If the mirror image of the point P(3,4,9) in the line (x-1)/3=(y+1)/2=(z-2)/1 is (α, β, γ), then 14 (α+β+γ) is:

If the mirror image of the point $\displaystyle P(3,4,9)$ in the line $\displaystyle \frac{x-1}{3}=\frac{y+1}{2}=\frac{z-2}{1}$ is $\displaystyle (\alpha, \beta, \gamma)$, then $\displaystyle 14$ $\displaystyle (\alpha+\beta+\gamma)$ is :
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