Mathematics · 2023
JEE Main · 31 January 2023, Shift 1 · Q74
If the maximum distance of normal to the ellipse x^2/4+y^2/b^2=1, b<2, from the origin is 1, then the eccentricity of the ellipse is:
If the maximum distance of normal to the ellipse $\displaystyle \frac{x^2}{4}+\frac{y^2}{b^2}=1, b<2$, from the origin is $\displaystyle 1$ , then the eccentricity of the ellipse is :
Official answer
From NTA’s final answer key for this paper.
(4)
$\displaystyle \frac{\sqrt{3}}{2}$
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JEE Main 2023 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.