Mathematics · 2013
JEE Main · 9 April 2013, Shift 1 · Q61
If the lines (x+1)/2=(y-1)/1=(z+1)/3 and (x+2)/2=(y- k)/3=z/4 are coplanar, then the value of k is:
If the lines $\displaystyle \frac{x+1}{2}=\frac{y-1}{1}=\frac{z+1}{3}$ and $\displaystyle \frac{x+2}{2}=\frac{y-\mathrm{k}}{3}=\frac{z}{4}$ are coplanar, then the value of k is :
Official answer
(1)
$\displaystyle \frac{11}{2}$
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JEE Main 2013 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.