Mathematics · 2013
JEE Main · 9 April 2013, Shift 1 · Q87
A vector n is inclined to x -axis at 45^°, to y -axis at 60^° and at an acute angle to z -axis. If n is a normal to a plane passing through the point…
A vector $\displaystyle \overrightarrow{\mathrm{n}}$ is inclined to $\displaystyle x$-axis at $\displaystyle 45^{\circ}$, to $\displaystyle y$-axis at $\displaystyle 60^{\circ}$ and at an acute angle to
$\displaystyle z$-axis. If $\displaystyle \overrightarrow{\mathrm{n}}$ is a normal to a plane passing through the point $\displaystyle (\sqrt{2},-1,1)$, then the equation of the plane is :
Official answer
(2)
$\displaystyle \sqrt{2} x+y+z=2$
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JEE Main 2013 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.