Mathematics · 2019
JEE Main · 10 April 2019, Shift 1 · Q81
If the line x-2 y=12 is tangent to the ellipse x^2/(a^2)+y^2/(b^2)=1 at the point (3, -9/2), then the length of the latus rectum of the ellipse is:
If the line $\displaystyle x-2 y=12$ is tangent to the ellipse $\displaystyle \frac{x^2}{\mathrm{a}^2}+\frac{y^2}{\mathrm{~b}^2}=1$ at the point $\displaystyle \left(3, \frac{-9}{2}\right)$, then the length of the latus rectum of the ellipse is :
Official answer
(1)
$\displaystyle 9$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.