Mathematics · 2019
JEE Main · 12 April 2019, Shift 1 · Q82
If the line (x-2)/3=(y+1)/2=(z-1)/-1 intersects the plane 2 x+3 y-z+13=0 at a point P and the plane 3 x+y+4 z=16 at a point Q, then PQ is equal to:
If the line $\displaystyle \frac{x-2}{3}=\frac{y+1}{2}=\frac{z-1}{-1}$ intersects the plane $\displaystyle 2 x+3 y-z+13=0$ at a point P and the plane $\displaystyle 3 x+y+4 z=16$ at a point Q , then PQ is equal to :
Official answer
(2)
$\displaystyle 2 \sqrt{14}$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.