Mathematics · 2019
JEE Main · 10 April 2019, Shift 2 · Q83
A perpendicular is drawn from a point on the line (x-1)/2=(y+1)/-1=z/1 to the plane x+y+z=3 such that the foot of the perpendicular Q also lies on…
A perpendicular is drawn from a point on the line $\displaystyle \frac{x-1}{2}=\frac{y+1}{-1}=\frac{z}{1}$ to the plane $\displaystyle x+y+z=3$ such that the foot of the perpendicular Q also lies on the plane $\displaystyle x-y+z=3$. Then the co-ordinates of Q are:
Official answer
(1)
($\displaystyle 2$, $\displaystyle 0$, $\displaystyle 1$)
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.