Mathematics · 2013
JEE Main · 25 April 2013, Shift 1 · Q71
If the integral ∫ (cos 8 x+1)/(cot 2 x- tan 2 x) d x=A cos 8 x+k, where k is an arbitrary constant, then A is equal to:
If the integral
$$\int \frac{\cos 8 x+1}{\cot 2 x-\tan 2 x} d x=A \cos 8 x+k,
$$
where k is an arbitrary constant, then A is equal to :
Official answer
(1)
$\displaystyle -\frac{1}{16}$
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JEE Main 2013 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.