Mathematics · 2024
JEE Main · 6 April 2024, Shift 2 · Q8
If the function f(x)=(1/x)^2 x; x>0 attains the maximum value at x=1/e then:
If the function $\displaystyle f(x)=\left(\frac{1}{x}\right)^{2 x} ; x>0$ attains the maximum value at $\displaystyle x=\frac{1}{\mathrm{e}}$ then :
Official answer
From NTA’s final answer key for this paper.
(1)
$\displaystyle \mathrm{e}^\pi>\pi^{\mathrm{e}}$
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JEE Main 2024 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.