Mathematics · 2021
JEE Main · 4 August 2021, Shift 1 · Q75
If the ellipse x^2/16+y^2/b^2=1 and the circle x^2+y^2=4 b intersect at an angle (π)/3, then a value of ' b ' is
If the ellipse $\displaystyle \frac{x^2}{16}+\frac{y^2}{b^2}=1$ and the circle $\displaystyle x^2+y^2=4 b$ intersect at an angle $\displaystyle \frac{\pi}{3}$, then a value of ' $\displaystyle b$ ' is
Official answer
(1)
$\displaystyle 10+2 \sqrt{21}$
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.