Mathematics · 2014
JEE Main · 9 April 2014, Shift 1 · Q71
If f(x) is continuous and f(9/2)=2 / 9, then lim_x → 0 f((1- cos 3 x)/x^2) is equal to:
If $\displaystyle f(x)$ is continuous and $\displaystyle f\left(\frac{9}{2}\right)=2 / 9$, then $\displaystyle \lim _{x \rightarrow 0} f\left(\frac{1-\cos 3 x}{x^2}\right)$ is equal to :
Official answer
(2)
$\displaystyle 2$/$\displaystyle 9$
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JEE Main 2014 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.