Mathematics · 2015
JEE Main · 10 April 2015, Shift 1 · Q70
lim_x → 0 (e^x^2- cos x)/(sin^2 x) is equal to:
$\displaystyle \lim _{x \rightarrow 0} \frac{\mathrm{e}^{x^2}-\cos x}{\sin ^2 x}$ is equal to :
Official answer
(2)
$\displaystyle \frac{3}{2}$
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JEE Main 2015 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.