Mathematics · 2019
JEE Main · 11 January 2019, Shift 2 · Q70
lim_x → 0 (x cot (4 x))/(sin^2 x cot^2(2 x)) is equal to:
$\displaystyle \lim _{x \rightarrow 0} \frac{x \cot (4 x)}{\sin ^2 x \cot ^2(2 x)}$ is equal to :
Official answer
(3)
$\displaystyle 1$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.