Mathematics · 2021
JEE Main · 25 July 2021, Shift 2 · Q64
If [x] be the greatest integer less than or equal to x, then Σ_n =8^100[((-1)^n n)/2] is equal to:
If $\displaystyle [x]$ be the greatest integer less than or equal to $\displaystyle x$, then $\displaystyle \sum_{\mathrm{n}=8}^{100}\left[\frac{(-1)^{\mathrm{n}} \mathrm{n}}{2}\right]$ is equal to :
Official answer
(4)
$\displaystyle 4$
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.