If a +α=1, b +β=2 and a f(x)+α f(1/x)= b x+(β)/x, x ≠ 0, then the value of the expression (f(x)+f(1/x))/(x+1/x) is \ \ \ \.

If $\displaystyle \mathrm{a}+\alpha=1, \mathrm{~b}+\beta=2$ and $\displaystyle \mathrm{a} f(x)+\alpha f\left(\frac{1}{x}\right)=\mathrm{b} x+\frac{\beta}{x}, x \neq 0$, then the value of the expression $\displaystyle \frac{f(x)+f\left(\dfrac{1}{x}\right)}{x+\dfrac{1}{x}}$ is \_\_\_\_.