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Mathematics · 2019

JEE Main · 9 January 2019, Shift 1 · Q61

For x ∈ R -{0,1}, let f_1(x)=1/x, f_2(x)=1-x and f_3(x)=1/(1-x) be three given functions. If a function, J(x) satisfies ( f_2 ° J ° f_1)(x)= f_3(x)…

For $\displaystyle x \in \mathbf{R}-\{0,1\}$, let $\displaystyle f_1(x)=\frac{1}{x}, f_2(x)=1-x$ and $\displaystyle f_3(x)=\frac{1}{1-x}$ be three given functions. If a function, $\displaystyle J(x)$ satisfies $\displaystyle \left(\mathrm{f}_2 \circ \mathrm{~J} \circ \mathrm{f}_1\right)(x)=\mathrm{f}_3(x)$ then $\displaystyle \mathrm{J}(x)$ is equal to :
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.