Mathematics · 2013
JEE Main · 25 April 2013, Shift 1 · Q90
A point on the ellipse, 4 x^2+9 y^2=36, where the normal is parallel to the line, 4 x-2 y-5=0, is:
A point on the ellipse, $\displaystyle 4 x^2+9 y^2=36$, where the normal is parallel to the line, $\displaystyle 4 x-2 y-5=0$, is :
Official answer
(1)
$\displaystyle \left(\frac{9}{5}, \frac{8}{5}\right)$
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JEE Main 2013 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.