Mathematics · 2019
JEE Main · 10 January 2019, Shift 2 · Q73
A helicopter is flying along the curve given by y-x^3 / 2=7,(x ≥ 0). A soldier positioned at the point (1/2, 7) wants to shoot down the helicopter…
A helicopter is flying along the curve given by $\displaystyle y-x^{3 / 2}=7,(x \geq 0)$. A soldier positioned at the point $\displaystyle \left(\frac{1}{2}, 7\right)$ wants to shoot down the helicopter when it is nearest to him. Then this nearest distance is :
Official answer
(4)
$\displaystyle \frac{1}{6} \sqrt{\frac{7}{3}}$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.