Mathematics · 2019
JEE Main · 10 January 2019, Shift 2 · Q72
The tangent to the curve, y=x e^x^2 passing through the point (1, e ) also passes through the point:
The tangent to the curve, $\displaystyle y=x \mathrm{e}^{x^2}$ passing through the point $\displaystyle (1, \mathrm{e})$ also passes through the point :
Official answer
(3)
$\displaystyle \left(\frac{4}{3}, 2 \mathrm{e}\right)$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.