Mathematics · 2019
JEE Main · 10 January 2019, Shift 1 · Q73
The shortest distance between the point (3/2, 0) and the curve y=√ x,(x>0), is:
The shortest distance between the point
$\displaystyle \left(\frac{3}{2}, 0\right)$ and the curve $\displaystyle y=\sqrt{x},(x>0)$, is :
Official answer
(1)
$\displaystyle \frac{\sqrt{5}}{2}$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.