When 600 mL of 0.2 M HNO_3 is mixed with 400 mL of 0.1 M NaOH solution in a flask, the rise in temperature of the flask is \ \ \ \ × 10^-2^° C.…

When $\displaystyle 600$ mL of $\displaystyle 0.2 \mathrm{M} \mathrm{HNO}_3$ is mixed with $\displaystyle 400$ mL of $\displaystyle 0.1$ M NaOH solution in a flask, the rise in temperature of the flask is \_\_\_\_ $\displaystyle \times 10^{-2}{ }^{\circ} \mathrm{C}$. (Enthalpy of neutralisation $\displaystyle =57 \mathrm{~kJ} \mathrm{~mol}^{-1}$ and Specific heat of water $\displaystyle =4.2 \mathrm{JK}^{-1} \mathrm{~g}^{-1}$ ) (Neglect heat capacity of flask)