Chemistry · 2023
JEE Main · 30 January 2023, Shift 2 · Q52
1 mole of ideal gas is allowed to expand reversibly and adiabatically from a temperature of 27^° C. The work done is 3 kJ mol^-1. The final…
$\displaystyle 1$ mole of ideal gas is allowed to expand reversibly and adiabatically from a temperature of $\displaystyle 27^{\circ} \mathrm{C}$. The work done is $\displaystyle 3 \mathrm{~kJ} \mathrm{~mol}^{-1}$. The final temperature of the gas is $\displaystyle \_\_\_\_$ K (Nearest integer). Given $\displaystyle \mathrm{C}_{\mathrm{V}}=20 \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}$
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JEE Main 2023 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.