Chemistry · 2026
JEE Main · 8 April 2026, Shift 2 · Q74
Consider the reaction 2 H_2 S ( g )+3 O_2( g ) → 2 H_2 O ( l )+2 SO_2( g ) The magnitude of enthalpy change for the reaction in kJ mol^-1 is ____.…
Consider the reaction
$\displaystyle 2 \mathrm{H}_2 \mathrm{~S}(\mathrm{~g})+3 \mathrm{O}_2(\mathrm{~g}) \rightarrow 2 \mathrm{H}_2 \mathrm{O}(\mathrm{l})+2 \mathrm{SO}_2(\mathrm{~g})$
The magnitude of enthalpy change for the reaction in $\displaystyle \mathrm{kJ} \mathrm{mol}^{-1}$ is $\displaystyle \_\_\_\_$. (Nearest integer)Given : $\displaystyle \Delta_{\mathrm{f}} \mathrm{H}^{\ominus}\left(\mathrm{H}_2 \mathrm{~S}\right)=-20.1 \mathrm{~kJ} \mathrm{~mol}^{-1}$
$$\begin{aligned}
& \Delta_{\mathrm{f}} \mathrm{H}^{\ominus}\left(\mathrm{H}_2 \mathrm{O}\right)=-286.0 \mathrm{~kJ} \mathrm{~mol}^{-1} \\
& \Delta_{\mathrm{f}} \mathrm{H}^{\ominus}\left(\mathrm{SO}_2\right)=-297.0 \mathrm{~kJ} \mathrm{~mol}^{-1}
\end{aligned}
$$
Official answer
From NTA’s final answer key for this paper.
1126
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JEE Main 2026 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.