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Chemistry · 2026

JEE Main · 8 April 2026, Shift 2 · Q74

Consider the reaction 2 H_2 S ( g )+3 O_2( g ) → 2 H_2 O ( l )+2 SO_2( g ) The magnitude of enthalpy change for the reaction in kJ mol^-1 is ____.…

Consider the reaction $\displaystyle 2 \mathrm{H}_2 \mathrm{~S}(\mathrm{~g})+3 \mathrm{O}_2(\mathrm{~g}) \rightarrow 2 \mathrm{H}_2 \mathrm{O}(\mathrm{l})+2 \mathrm{SO}_2(\mathrm{~g})$ The magnitude of enthalpy change for the reaction in $\displaystyle \mathrm{kJ} \mathrm{mol}^{-1}$ is $\displaystyle \_\_\_\_$. (Nearest integer)Given : $\displaystyle \Delta_{\mathrm{f}} \mathrm{H}^{\ominus}\left(\mathrm{H}_2 \mathrm{~S}\right)=-20.1 \mathrm{~kJ} \mathrm{~mol}^{-1}$ $$\begin{aligned} & \Delta_{\mathrm{f}} \mathrm{H}^{\ominus}\left(\mathrm{H}_2 \mathrm{O}\right)=-286.0 \mathrm{~kJ} \mathrm{~mol}^{-1} \\ & \Delta_{\mathrm{f}} \mathrm{H}^{\ominus}\left(\mathrm{SO}_2\right)=-297.0 \mathrm{~kJ} \mathrm{~mol}^{-1} \end{aligned} $$
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JEE Main 2026 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.