Chemistry · 2026
JEE Main · 2 April 2026, Shift 1 · Q54
Consider the following data. (i) 2 Al ( s )+6 HCl ( aq ) → Al_2 Cl_6( aq )+3 H_2( g )+1200 kJ / mol (ii) H_2( g )+ Cl_2( g ) → 2 HCl ( g )+164 kJ /…
Consider the following data.
(i)
$\displaystyle 2 \mathrm{Al}(\mathrm{s})+6 \mathrm{HCl}(\mathrm{aq}) \rightarrow \mathrm{Al}_2 \mathrm{Cl}_6(\mathrm{aq})+3 \mathrm{H}_2(\mathrm{~g})+1200 \mathrm{~kJ} / \mathrm{mol}$
(ii)
$\displaystyle \mathrm{H}_2(\mathrm{~g})+\mathrm{Cl}_2(\mathrm{~g}) \rightarrow 2 \mathrm{HCl}(\mathrm{g})+164 \mathrm{~kJ} / \mathrm{mol}$.
(iii)
$\displaystyle \mathrm{HCl}(\mathrm{g})+\mathrm{aq} \rightarrow \mathrm{HCl}(\mathrm{aq})+83 \mathrm{~kJ} / \mathrm{mol}$.
(iv)
$\displaystyle \mathrm{Al}_2 \mathrm{Cl}_6(\mathrm{~s})+\mathrm{aq} \rightarrow \mathrm{Al}_2 \mathrm{Cl}_6(\mathrm{aq})+663 \mathrm{~kJ} / \mathrm{mol}$
The enthalpy of formation of anhydrous solid $\displaystyle \mathrm{Al}_2 \mathrm{Cl}_6$ is :
Official answer
From NTA’s final answer key for this paper.
(4)
$\displaystyle -1527 \mathrm{~kJ} \mathrm{~mol}^{-1}$
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JEE Main 2026 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.