Chemistry · 2025
JEE Main · 23 January 2025, Shift 1 · Q54
Ice at -5^° C is heated to become vapor with temperature of 110^° C at atmospheric pressure. The entropy change associated with this process can be…
Ice at $\displaystyle -5^{\circ} \mathrm{C}$ is heated to become vapor with temperature of $\displaystyle 110^{\circ} \mathrm{C}$ at atmospheric pressure. The entropy change associated with this process can be obtained from
Official answer
From NTA’s final answer key for this paper.
(1)
$\displaystyle \int_{268 \mathrm{~K}}^{273 \mathrm{~K}} \frac{\mathrm{C}_{\mathrm{p}, \mathrm{~m}}}{\mathrm{~T}} \mathrm{dT}+\frac{\Delta \mathrm{H}_{\mathrm{m}}, \text { fusion }}{\mathrm{T}_{\mathrm{f}}}+\frac{\Delta \mathrm{H}_{\mathrm{m}, \text { vaporisation }}}{\mathrm{T}_{\mathrm{b}}}+\int_{273 \mathrm{~K}}^{373 \mathrm{~K}} \frac{\mathrm{C}_{\mathrm{p}, \mathrm{~m}} \mathrm{dT}}{\mathrm{~T}}+\int_{373 \mathrm{~K}}^{383 \mathrm{~K}} \frac{\mathrm{C}_{\mathrm{p}, \mathrm{~m}} \mathrm{dT}}{\mathrm{~T}}$
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JEE Main 2025 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.