Chemistry · 2021
JEE Main · 27 July 2021, Shift 1 · Q53
For water at 100^° C and 1 bar, Δ_vap H -Δ_vap U = \ \ \ \ × 10^2 J mol^-1. (Round off to the Nearest Integer) [. Use:. R =8.31 J mol^-1 K^-1]…
For water at $\displaystyle 100^{\circ} \mathrm{C}$ and $\displaystyle 1$ bar ,
$\displaystyle \Delta_{\text {vap }} \mathrm{H}-\Delta_{\text {vap }} \mathrm{U}=$ \_\_\_\_ $\displaystyle \times 10^2 \mathrm{~J} \mathrm{~mol}^{-1}$. (Round off to the Nearest Integer)
$\displaystyle \left[\right.$ Use : $\displaystyle \left.\mathrm{R}=8.31 \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}\right]$
[Assume volume of $\displaystyle \mathrm{H}_2 \mathrm{O}(\mathrm{l})$ is much smaller than volume of $\displaystyle \mathrm{H}_2 \mathrm{O}(\mathrm{g})$. Assume $\displaystyle \mathrm{H}_2 \mathrm{O}(\mathrm{g})$ can be treated as an ideal gas]
Official answer
31
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JEE Main 2021 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.