Chemistry · 2020
JEE Main · 8 January 2020, Shift 1 · Q48
What would be the electrode potential for the given half cell reaction at pH =5? \ \ \ \. 2 H_2 O → O_2+4 H^ +4 e^-; E_red^0=1.23 V; ( R =8.314 J…
What would be the electrode potential for the given half cell reaction at $\displaystyle \mathrm{pH}=5$ ?
\_\_\_\_.
$$\begin{gathered}
2 \mathrm{H}_2 \mathrm{O} \rightarrow \mathrm{O}_2+4 \mathrm{H}^{\oplus}+4 \mathrm{e}^{-} ; \mathrm{E}_{\mathrm{red}}^0=1.23 \mathrm{~V} \\
\left(\mathrm{R}=8.314 \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1} ; \text { Temp }=298 \mathrm{~K} ;\right. \\
\text { oxygen under std. atm. pressure of } 1 \mathrm{bar})
\end{gathered}
$$
Official answer
−0.935 ± 0.005
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JEE Main 2020 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.