Chemistry · 2022
JEE Main · 30 July 2022, Shift 2 · Q39
The E^° (volt) values are: Al^3+ / Al,-1.66, Sc^3+ / Sc,-2.08, Fe^3+ / Fe^2+, +0.77, Hg_2^2+ / Hg,+0.79. Arrangement of cations, Al^3+, Sc^3+, Fe^3+…
The $\displaystyle \mathrm{E}^{\circ}$ (volt) values are : $\displaystyle \mathrm{Al}^{3+} / \mathrm{Al},-1.66, \mathrm{Sc}^{3+} / \mathrm{Sc},-2.08, \mathrm{Fe}^{3+} / \mathrm{Fe}^{2+}$, $\displaystyle +0.77, \mathrm{Hg}_2{ }^{2+} / \mathrm{Hg},+0.79$. Arrangement of cations, $\displaystyle \mathrm{Al}^{3+}, \mathrm{Sc}^{3+}, \mathrm{Fe}^{3+}$ and $\displaystyle \mathrm{Hg}_2{ }^{2+}$ in decreasing order of oxidizing strength is
Official answer
(3)
$\displaystyle \mathrm{Hg}_2^{2+}>\mathrm{Fe}^{3+}>\mathrm{Al}^{3+}>\mathrm{Sc}^{3+}$
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JEE Main 2022 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.