Resistance of a conductivity cell (cell constant 129 m^-1 ) filled with 74.5 ppm solution of KCl is 100 Ω (labelled as solution 1). When the same…

Resistance of a conductivity cell (cell constant $\displaystyle 129 \mathrm{~m}^{-1}$ ) filled with $\displaystyle 74.5$ ppm solution of KCl is $\displaystyle 100 \Omega$ (labelled as solution $\displaystyle 1$). When the same cell is filled with KCl solution of $\displaystyle 149$ ppm, the resistance is $\displaystyle 50 \Omega$ (labelled as solution $\displaystyle 2$). The ratio of molar conductivity of solution $\displaystyle 1$ and solution $\displaystyle 2$ is i.e. $\displaystyle \frac{\Lambda_1}{\Lambda_2}=x \times 10^{-3}$. The value of $\displaystyle x$ is \_\_\_\_. (Nearest integer) Given, molar mass of KCl is $\displaystyle 74.5 \mathrm{~g} \mathrm{~mol}^{-1}$.