Chemistry · 2022
JEE Main · 30 July 2022, Shift 2 · Q55
For the given cell Zn ( s )| Zn^2+( C_1, M ) ∥ Zn^2+( C_2 M )| Zn ( s ) the change in Gibbs energy (Δ G ) will be zero when (C_1)/(C_2) is equal to \…
For the given cell $\displaystyle \mathrm{Zn}(\mathrm{s})\left|\mathrm{Zn}^{2+}\left(\mathrm{C}_1, \mathrm{M}\right) \| \mathrm{Zn}^{2+}\left(\mathrm{C}_2 \mathrm{M}\right)\right| \mathrm{Zn}(\mathrm{s})$ the change in Gibbs energy $\displaystyle (\Delta \mathrm{G})$ will be zero when $\displaystyle \frac{\mathrm{C}_1}{\mathrm{C}_2}$ is equal to \_\_\_\_.
Official answer
1
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JEE Main 2022 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.