For an electrochemical cell Sn ( s )| Sn^2+( aq, 1 M )|| Pb^2+( aq, 1 M )| Pb ( s ) the ratio ([ Sn^2+])/([ Pb^2+]) when this cell attains…

For an electrochemical cell $$\mathrm{Sn}(\mathrm{~s})\left|\mathrm{Sn}^{2+}(\mathrm{aq}, 1 \mathrm{M})\right|\left|\mathrm{Pb}^{2+}(\mathrm{aq}, 1 \mathrm{M})\right| \mathrm{Pb}(\mathrm{~s}) $$ the ratio $\displaystyle \frac{\left[\mathrm{Sn}^{2+}\right]}{\left[\mathrm{Pb}^{2+}\right]}$ when this cell attains equilibrium is \_\_\_\_. $$\begin{aligned} & \left(\text { Given }: \mathrm{E}_{\mathrm{Sn}^{2+} \mid \mathrm{Sn}}^0=-0.14 \mathrm{~V},\right. \\ & \left.\mathrm{E}_{\mathrm{Pb}^{2+} \mid \mathrm{Pb}}^0=-0.13 \mathrm{~V}, \frac{2.303 \mathrm{RT}}{\mathrm{~F}}=0.06\right) \end{aligned} $$