Chemistry · 2025
JEE Main · 7 April 2025, Shift 1 · Q53
Total enthalpy change for freezing of 1 mol of water at 10^° C to ice at -10^° C is ____ (Given: Δ_fus H =x kJ / mol C_p [ H_2 O ( l )]=y J mol^-1…
Total enthalpy change for freezing of $\displaystyle 1$ mol of water at $\displaystyle 10^{\circ} \mathrm{C}$ to ice at $\displaystyle -10^{\circ} \mathrm{C}$ is $\displaystyle \_\_\_\_$
(Given: $\displaystyle \Delta_{\text {fus }} \mathrm{H}=x \mathrm{~kJ} / \mathrm{mol}$
$\displaystyle \mathrm{C}_{\mathrm{p}}\left[\mathrm{H}_2 \mathrm{O}(\mathrm{l})\right]=y \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}$
$\displaystyle \mathrm{C}_{\mathrm{p}}\left[\mathrm{H}_2 \mathrm{O}(\mathrm{s})\right]=z \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}$
Official answer
From NTA’s final answer key for this paper.
(2)
$\displaystyle -10(100 x+y+z)$
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JEE Main 2025 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.