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Chemistry · 2025

JEE Main · 4 April 2025, Shift 2 · Q52

Consider the given data: (a) HCl ( g )+10 H_2 O ( l ) → HCl.10 H_2 O Δ H =-69.01 kJ mol^-1 (b) HCl ( g )+40 H_2 O ( l ) → HCl.40 H_2 O Δ H =-72.79 kJ…

Consider the given data :
(a)
$\displaystyle \mathrm{HCl}(\mathrm{g})+10 \mathrm{H}_2 \mathrm{O}(\mathrm{l}) \rightarrow \mathrm{HCl} .10 \mathrm{H}_2 \mathrm{O} \Delta \mathrm{H}=-69.01 \mathrm{~kJ} \mathrm{~mol}^{-1}$
(b)
$\displaystyle \mathrm{HCl}(\mathrm{g})+40 \mathrm{H}_2 \mathrm{O}(\mathrm{l}) \rightarrow \mathrm{HCl} .40 \mathrm{H}_2 \mathrm{O} \Delta \mathrm{H}=-72.79 \mathrm{~kJ} \mathrm{~mol}^{-1}$
Choose the correct statement :
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JEE Main 2025 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.