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Chemistry · 2021

JEE Main · 3 August 2021, Shift 2 · Q54

The work done by an ideal monoatomic gas when it is taken along the path ABCD as shown in the figure is xP_0 V_0. The value of (- x ) is \ \ \ \.…

The work done by an ideal monoatomic gas when it is taken along the path ABCD as shown in the figure is $\displaystyle \mathrm{xP}_0 \mathrm{~V}_0$. The value of $\displaystyle (-\mathrm{x})$ is \_\_\_\_. (Nearest integer) $$[\ln 2=0.69] $$ Figure: JEE Main Chemistry 2021, Chemical Thermodynamics
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JEE Main 2021 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.