Chemistry · 2022
JEE Main · 25 June 2022, Shift 1 · Q84
The standard entropy change for the reaction 4 Fe ( s )+3 O_2( g ) → 2 Fe_2 O_3( s ) is -550 J K^-1 at 298 K. [Given: The standard enthalpy change…
The standard entropy change for the reaction $\displaystyle 4 \mathrm{Fe}(\mathrm{s})+3 \mathrm{O}_2(\mathrm{~g}) \rightarrow 2 \mathrm{Fe}_2 \mathrm{O}_3(\mathrm{~s})$ is -$\displaystyle 550$ $\displaystyle \mathrm{J} \mathrm{K}^{-1}$ at $\displaystyle 298$ K.
[Given : The standard enthalpy change for the reaction is $\displaystyle -165 \mathrm{~kJ} \mathrm{~mol}^{-1}$ ]. The temperature in K at which the reaction attains equilibrium is \_\_\_\_. (Nearest Integer)
Official answer
300
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JEE Main 2022 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.