Chemistry · 2020
JEE Main · 3 September 2020, Shift 1 · Q48
The photoelectric current from Na (work function, w_0=2.3 eV ) is stopped by the output voltage of the cell Pt ( s )| H_2( g, 1 bar )| HCl ( aq., pH…
The photoelectric current from Na (work function, $\displaystyle \mathrm{w}_0=2.3 \mathrm{eV}$ ) is stopped by the output voltage of the cell
$$\begin{aligned}
& \mathrm{Pt}(\mathrm{~s})\left|\mathrm{H}_2(\mathrm{~g}, 1 \mathrm{bar})\right| \mathrm{HCl}(\mathrm{aq} ., \mathrm{pH}=1)|\mathrm{AgCl}(\mathrm{~s})| \\
& \mathrm{Ag}(\mathrm{~s}) .
\end{aligned}
$$
The pH of $\displaystyle \mathrm{aq} . \mathrm{HCl}$ required to stop the photoelectric current from $\displaystyle \mathrm{K}\left(\mathrm{w}_0=2.25 \mathrm{eV}\right)$, all other conditions remaining the same, is \_\_\_\_ $\displaystyle \times 10^{-2}$ (to the nearest integer).Given,
$$2.303 \frac{\mathrm{RT}}{\mathrm{~F}}=0.06 \mathrm{~V} ; \mathrm{E}_{\mathrm{AgCl} \mid \mathrm{Ag} \mid \mathrm{Cl}^{-}}^0=0.22 \mathrm{~V}
$$
Official answer
58
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JEE Main 2020 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.