SolveIt is under development
SolveItJEE Main
Question 153 / 161 · latest first
Chemistry · 2020

JEE Main · 3 September 2020, Shift 1 · Q48

The photoelectric current from Na (work function, w_0=2.3 eV ) is stopped by the output voltage of the cell Pt ( s )| H_2( g, 1 bar )| HCl ( aq., pH…

The photoelectric current from Na (work function, $\displaystyle \mathrm{w}_0=2.3 \mathrm{eV}$ ) is stopped by the output voltage of the cell $$\begin{aligned} & \mathrm{Pt}(\mathrm{~s})\left|\mathrm{H}_2(\mathrm{~g}, 1 \mathrm{bar})\right| \mathrm{HCl}(\mathrm{aq} ., \mathrm{pH}=1)|\mathrm{AgCl}(\mathrm{~s})| \\ & \mathrm{Ag}(\mathrm{~s}) . \end{aligned} $$ The pH of $\displaystyle \mathrm{aq} . \mathrm{HCl}$ required to stop the photoelectric current from $\displaystyle \mathrm{K}\left(\mathrm{w}_0=2.25 \mathrm{eV}\right)$, all other conditions remaining the same, is \_\_\_\_ $\displaystyle \times 10^{-2}$ (to the nearest integer).Given, $$2.303 \frac{\mathrm{RT}}{\mathrm{~F}}=0.06 \mathrm{~V} ; \mathrm{E}_{\mathrm{AgCl} \mid \mathrm{Ag} \mid \mathrm{Cl}^{-}}^0=0.22 \mathrm{~V} $$
ShareWhatsAppTelegram

More from Electrochemistry

JEE Main 2020 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.