For the disproportionation reaction 2 Cu^+( aq ) ⇌ Cu ( s )+ Cu^2+( aq ) at 298 K, ln K (where K is the equilibrium constant) is \ \ \ \ × 10^-1.…

For the disproportionation reaction $\displaystyle 2 \mathrm{Cu}^{+}(\mathrm{aq}) \rightleftharpoons \mathrm{Cu}(\mathrm{s})+\mathrm{Cu}^{2+}(\mathrm{aq})$ at $\displaystyle 298$ K, $\displaystyle \ln \mathrm{K}$ (where K is the equilibrium constant) is \_\_\_\_ $\displaystyle \times 10^{-1}$.Given : $$\begin{aligned} & \left(\mathrm{E}_{\mathrm{Cu}^{2+} / \mathrm{Cu}^{+}}^0=0.16 \mathrm{~V}\right. \\ & \mathrm{E}_{\mathrm{Cu}^{+} / \mathrm{Cu}}^0=0.52 \mathrm{~V} \\ & \left.\frac{\mathrm{RT}}{\mathrm{~F}}=0.025\right) \end{aligned} $$