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Chemistry · 2024

JEE Main · 29 January 2024, Shift 2 · Q89

The half-life of radioisotope bromine - 82 is 36 hours. The fraction which remains after one day is ____ × 10^-2. (Given antilog 0.2006=1.587 )

The half-life of radioisotope bromine - $\displaystyle 82$ is $\displaystyle 36$ hours. The fraction which remains after one day is $\displaystyle \_\_\_\_$ $\displaystyle \times 10^{-2}$. (Given antilog $\displaystyle 0.2006=1.587$ )
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