Decomposition of a hydrocarbon follows the equation k =(5.5 × 10^11 s^-1) e^((-28000 K)/T). The activation energy of reaction is ____ kJ mol^-1.…

Decomposition of a hydrocarbon follows the equation $\displaystyle \mathrm{k}=\left(5.5 \times 10^{11} \mathrm{~s}^{-1}\right) \mathrm{e}^{\frac{-28000 \mathrm{~K}}{\mathrm{~T}}}$. The activation energy of reaction is $\displaystyle \_\_\_\_$ $\displaystyle \mathrm{kJ} \mathrm{mol}^{-1}$. (Nearest Integer) Given : $\displaystyle \mathrm{R}=8.3 \mathrm{~J} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}$