Pre-exponential factors of two different reactions of same order are identical. Let activation energy of first reaction exceeds the activation energy…

Pre-exponential factors of two different reactions of same order are identical. Let activation energy of first reaction exceeds the activation energy of second reaction by $\displaystyle 20 \mathrm{~kJ} \mathrm{~mol}^{-1}$. If $\displaystyle \mathrm{k}_1$ and $\displaystyle \mathrm{k}_2$ are the rate constants of first and second reaction respectively at $\displaystyle 300$ K , then $\displaystyle \ln \frac{\mathrm{k}_2}{\mathrm{k}_1}$ will be $\displaystyle \_\_\_\_$. (nearest integer) $\displaystyle \left[\mathrm{R}=8.3 \mathrm{~J} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}\right]$